https://mathtuition88.com/group-tuition/
Maths Tuition @ Bishan starting in 2014.
Secondary 4 O Level E Maths and A Maths.
Patient and Dedicated Maths Tutor (NUS Maths Major 1st Class Honours, Dean’s List, RI Alumni)
Email: mathtuition88@gmail.com
https://mathtuition88.com/group-tuition/
Maths Tuition @ Bishan starting in 2014.
Secondary 4 O Level E Maths and A Maths.
Patient and Dedicated Maths Tutor (NUS Maths Major 1st Class Honours, Dean’s List, RI Alumni)
Email: mathtuition88@gmail.com
Firstly, apologies for the long gap. Very far from being Theorem of the Week, I know. Here’s another theorem for now, and I’ll do what I can to revert to a weekly post.
So, to this week’s theorem. I have previously promised to write about Fermat‘s Little Theorem, and I think it’s time to keep that promise. In that post (Theorem 10, about Lagrange’s theorem in group theory), I introduced the theorem, so I’m going to state it straightaway. If you haven’t seen the statement before, I suggest you look back at that post to see an example.
Theorem (Fermat’s Little Theorem) Let $latex p$ be a prime, and let $latex a$ be an integer not divisible by $latex p$. Then $latex a^{p-1} \equiv 1\mod{p}$.
If you aren’t comfortable with the notation of modular arithmetic, you might like to phrase the conclusion of the theorem as saying that $latex…
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Senior Wrangler is the First position in the Math Tripos in Cambridge. Singapore Prime Minister Lee Hsien Loong was the Senior Wrangler in 1973, the first Singaporean student with such great honors, among other senior wranglers like Arthur Cayley (Group Theory), J.J. Sylvester (Inventor of Matrix, private tuitor of the “inventor of Nursing” Florence Nightingale), J.E. Littlewood (partnered in a twin research team with G.H. Hardy), Frank Ramsey (Ramsey’s Theorem), Stokes, Pell, etc.
Some great mathematicians like Bertrand Russell (Logician, Nobel Litterature Prize) , G.H. Hardy (20th century greatest Pure Mathematician, mentored 2 geniuses: Indian Ramanujian and Chinese Hua Luogeng 华罗庚*) were not Senior Wrangler. Prof Hardy hated Math Tripos syllabus (revealed in his autobiography: “A Mathematician’s Apology“).
1914 Brian Charles Molony
1923 Frank Ramsey
1928 Donald Coxeter
1930 Jacob Bronowski
1939 James Wilkinson
1940 Hermann Bondi
1952 John Polkinghorne
1953 Crispin Nash-Williams
1959 Jayant Narlikar
1970 Derek…
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Attached below are the Formula Lists for E Maths and A Maths (O Level)
Do be familiar with all the formulas for Elementary Maths and Additional Maths inside, so that you know where to find it when needed!
Wishing everyone reading this all the best for their exams. 🙂
For Mathematics Tuition, contact Mr Wu at:
Email: mathtuition88@gmail.com
Tutor profile: About Tutor
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Math Doesn’t Suck: How to Survive Middle-School Math Without Losing Your Mind or Breaking a Nail
Secrets of Mental Math: The Mathemagician’s Guide to Lightning Calculation and Amazing Math Tricks
Synopsis: ‘I have a truly marvellous demonstration of this proposition which this margin is too narrow to contain.’
It was with these words, written in the 1630s, that Pierre de Fermat intrigued and infuriated the mathematics community. For over 350 years, proving Fermat’s Last Theorem was the most notorious unsolved mathematical problem, a puzzle whose basics most children could grasp but whose solution eluded the greatest minds in the world. In 1993, after years of secret toil, Englishman Andrew Wiles announced to an astounded audience that he had cracked Fermat’s Last Theorem. He had no idea of the nightmare that lay ahead.
In ‘Fermat’s Last Theorem’ Simon Singh has crafted a remarkable tale of intellectual endeavour spanning three centuries, and a moving testament to the obsession, sacrifice and extraordinary determination of Andrew Wiles: one man against all the odds.
First Published: 1997, Reissued: 2002| ISBN-13: 978-1841157917
Author’s…
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► See the top performers in reading, mathematics and science (on this page).
Chart A2·1 [ page 42] ranks countries, in descending order, according to the percentage of adults who have completed an upper secondary education (the most recent data in the 2013 report is from 2011).

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Greenland Central School - Math In Focus
I suppose every reader of this ‘ere blog will know Heron’s formula for the area $latex K$ of a triangle with sides $latex a,b,c$:
$latex K = \sqrt{s(s-a)(s-b)(s-c)}$
where $latex s$ is the “semi-perimeter”:
$latex \displaystyle{s=\frac{a+b+c}{2}.}$
The formula is not at all hard to prove: see the Wikipedia page for two elementary proofs.
However, I have only recently become aware of Brahmagupta’s formula for the area of a cyclic quadrilateral. A cyclic quadrilateral, if you didn’t know, is a (convex) quadrilateral all of whose points lie on a circle:
And if the edges have lengths $latex a,b,c,d$ as shown, then the formula states that the area is given by
$latex K = \sqrt{(s-a)(s-b)(s-c)(s-d)}$
where as above $latex s$ is the semi-perimeter:
$latex \displaystyle{s=\frac{a+b+c+d}{2}.}$
This can be seen to be a generalization of Heron’s formula. Although the formula is named for Brahmagupta (598 – 670), who does indeed seem to…
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Recently, in The Conversation, the Vice Chancellor of Monash University, wrote an article discussing MOOCs. He made some criticisms about the nature of assessment and grading that MOOCs offer. However, my attention was grabbed by two sentences:
The other major problem the MOOCs haven’t solved is assessment. They work very well for subjects like maths, which have objectively right and wrong answers, and can therefore be pretty easily marked by computers.
Now, here we have the Vice Chancellor of one of Australia’s leading universities – and indeed, one of the world’s leading universities (and incidently the University where I did both my Masters and my PhD) demonstrating an extraordinary lack of understanding about the fundamental nature of mathematics. He seems to think that mathematics is all about teaching students (in the fine words of John Power from Leeds University) about “finding ‘x'”. I suppose he thinks this…
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WordPress.com supports LaTeX, a document markup language for the TeX typesetting system, which is used widely in academia as a way to format mathematical formulas and equations. LaTeX makes it easier for math and computer science bloggers and other academics in our community to publish their work and write about topics they care about.
If you’re a math genius — many of you are! — and you’ve blogged about equations you’ve worked on, you’ve probably used LaTeX before. If you’re just starting out (or simply curious to see how it all works), we’ve gathered a few examples of great math and computing blogs on WordPress.com that will inspire you.
In general, to display formulas and equations, you place LaTeX code in between $latex and $, like this:
$latex YOUR LATEX CODE HERE$
So for example, inserting this when you’re creating a post . . .
$latex i\hbar\frac{\partial}{\partial…
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Question: (Broadrick Sec Prelim Add Math Paper 1 2010, Q8b)
In the expansion of , in descending powers of
, the seventh term is independent of
. Find the value of
and the value of this term.
Solution:
since it is the seventh term (recall
)
(independent of
means power is 0)
(Ans)
Prove
$latex x^{2} \equiv 3411 \mod 3457 $
has no solution?
Legendre Symbol:
$latex \displaystyle
x^{2} \equiv a \mod p
\iff
\boxed{
\left( \frac {a}{p} \right)
= \begin{cases}
-1, & \text{if 0 solution} \\
0 , & \text{if 1 solution} \\
1, & \text{if 2 solutions} \\
\end{cases}
}
$
Hint: prove $latex \left( \frac{3411}{3457} \right) = -1$
Using the Law of Quadratic Reciprocity, without computations, we can prove there is no solution for this equation.
Solution:
1.
3411 = 3 x 3 x 379 = 9 x 379
$Latex \displaystyle
\boxed{
\left(\frac{a}{p}\right)
\left(\frac{b}{p} \right)=
\left(\frac{ab}{p}\right)
}
$
$latex \displaystyle
\left(\frac{3411}{3457} \right)=
\left(\frac{9}{3457} \right).\left(\frac{379}{3457} \right)=
\left(\frac{379}{3457} \right)
$
since
$latex \displaystyle\left(\frac{9}{3457} \right)=1 $
because 9 is a perfect square, 3457 is prime.
2. By Quadratic Reciprocity,
$latex \displaystyle
\boxed{
\text{If p or q or both are } \equiv 1 \mod 4 \implies
\left(\frac{p}{q} \right)=
\left(\frac{q}{p} \right)}
$
Since
$latex…
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Математика Обучение центр
Maths Tuition Centre
The famous Singapore Math for children in primary schools is based on visual models.
The Singapore Ministry of Education has published a new 2013 Math syllabus for primary and secondary schools, which will roll out in examinations within 4 to 6 years. Todate only Primary 1 and Secondary 1 Math syllabuses are published here:
Who wins?
This comic video illustrates Singapore Math’s Arithmetics Polya-style problem solving process vs Algebra’s mechanical method.
The problem is as follow:
R is 3 times older than S two years ago. From now 2 years later, their total age is 32. How old is R now ?
See my previous blog (search “Monkey”) the Nobel Physicist Paul Dirac’s problem “The Monkeys and Coconuts“, 3 methods are used: 2 adanced modern math (by Sequence, eigenvector & eigenvalue), and the easiest & intuitive method (by Singapore Modelling Math). High-school Algebra method is impossible, if not cumbersome, to solve the Monkey problem !
Source: http://www.artofproblemsolving.com/Resources/Papers/SatoNT.pdf
Excellent notes on Olympiad Number Theory!
Preface:
This set of notes on number theory was originally written in 1995 for students
at the IMO level. It covers the basic background material that an IMO
student should be familiar with. This text is meant to be a reference, and
not a replacement but rather a supplement to a number theory textbook;
several are given at the back. Proofs are given when appropriate, or when
they illustrate some insight or important idea. The problems are culled from
various sources, many from actual contests and olympiads, and in general
are very difficult. The author welcomes any corrections or suggestions.
I find Khan Linear Algebra video excellent. The founder / teacher Sal Khan has the genius to explain this not-so-easy topic in modular videos steps by steps, from 2-dimensional vectors to 3-dimensional, working with you by hand to compute eigenvalues and eigenvectors, and show you what they mean in graphic views.
If you are taking Linear Algebra course in university, or revising it, just go through all the Khan’s short (5-20 mins) videos on Linear Algebra here:
In 138 lessons sequence:
http://theopenacademy.com/content/linear-algebra-khan-academy
or random revision:
Relationship-Mapping-Inverse (RMI)
(invented by Prof Xu Lizhi 徐利治 中国数学家 http://baike.baidu.com/view/6383.htm)
Find Z = a*b
By RMI Technique:
Let f Homomorphism: f(a*b) = f(a)+f(b)
Let f = log
log: R+ –> R
=> log (a*b) = log a + log b
1. Calculate log a (=X), log b (=Y)
2. X+Y = log (a*b)
3. Find Inverse log (a*b)
4. ANSWER: Z = a*b
Prove:
$latex \sqrt{2}^{\sqrt{2}^{\sqrt{2}}}= 2$
1. Take f = log for Mapping:
$latex \log\sqrt{2}^{\sqrt{2}^{\sqrt{2}}} $
$latex = \sqrt{2}\log\sqrt{2}^{\sqrt{2}}$
$latex = \sqrt{2}\sqrt{2}\log\sqrt{2} $
$latex = 2\log\sqrt{2} $
$latex = \log (\sqrt{2})^2 $
$latex = \log 2$
2. Inverse of log (bijective):
$latex \log \sqrt{2}^{\sqrt{2}^{\sqrt{2}}}= \log 2$
$latex \sqrt{2}^{\sqrt{2}^{\sqrt{2}}}= 2$
Prof Su 苏步青, the founding pioneer Math professor of the China’s top universities (Zhejiang 浙江大学 and Fudan 复旦大学), was one of the few mathematicians who had longevity above 100 years old (the other was French Mathematician Hadammard).
http://en.m.wikipedia.org/wiki/Su_Buqing
Two men A and B are 100 km apart, walking towards each other, A at speed 6 km/hour and B at 4 km/hour.
A brings a dog which runs at 10 km/hour between them, starting from A towards B, upon reaching B it runs back to reach A, then back to B again, and so on…
Find total distance the dog has covered when A and B finally meet ?
[Note: the content of this post is standard number theoretic material that can be found in many textbooks (I am relying principally here on Iwaniec and Kowalski); I am not claiming any new progress on any version of the Riemann hypothesis here, but am simply arranging existing facts together.]
The Riemann hypothesis is arguably the most important and famous unsolved problem in number theory. It is usually phrased in terms of the Riemann zeta function $latex {\zeta}&fg=000000$, defined by
$latex \displaystyle \zeta(s) = \sum_{n=1}^\infty \frac{1}{n^s}&fg=000000$
for $latex {\hbox{Re}(s)>1}&fg=000000$ and extended meromorphically to other values of $latex {s}&fg=000000$, and asserts that the only zeroes of $latex {\zeta}&fg=000000$ in the critical strip $latex {\{ s: 0 \leq \hbox{Re}(s) \leq 1 \}}&fg=000000$ lie on the critical line $latex {\{ s: \hbox{Re}(s)=\frac{1}{2} \}}&fg=000000$.
One of the main reasons that the Riemann hypothesis is so important to number theory is that the zeroes of…
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Mathematics, Learning and Technology
A collection of excellent free resources for demonstrating the various circle theorems:
Tim Devereux has created GeoGebra applets which allow exploration of the circle theorems. You can access each theorem from the menu on the left which includes a useful summary of all the theorems.


See alsothese excellent demonstrations.
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Mathematics, Learning and Technology
Top >10 Mathematics Websites remains a very popular post on this blog.
I have read various ‘Top (insert number here) Mathematics Websites’ posts and all of them have left me with the thought that so many excellent sites are missing from such lists. Any post claiming top 10 or >10 in my case is clearly the author’s top 10, notthe top 10! These are my top >10 because I really do use them – a lot – in the classroom! For my own list, I have decided to include some categories as well as individual sites which gives me the excuse to mention far more than 10! Note that every site mentioned here is free to use.
njwildberger: tangential thoughts
A quick quiz: which of the following four words doesn’t fit with the others??
Massive/Open/Online/Courses
We are going to muse about MOOCs today, a hot and highly debated topic in higher education circles. Are these ambitious new approaches to delivering free high quality education through online videos and interactive participation over the web going to put traditional universities out of business, or are they just one in a long historical line of hyped technologies that get everyone excited, and then fail to deliver the goods? (Think of the radio, TV, correspondence courses, movies, the tape recorder, the computer; all of which held out some promise for getting us to learn more and learn better, mostly to little avail, although the jury is still out on the computer.)
It’s fun to speculate on future trends, because of the potential—indeed likelihood—0f embarrassment for false predictions. Here is the summary of my argument today:…
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Excellent article on learning maths based on a growth mindset.
As you can see from the picture, it was a packed house! After waiting in line for fifteen minutes, I was so lucky (and excited) to get a seat to hear Jo Boaler speak, even if my seat was in the next to last row.
Jo opened the presentation with Dweck’s research on mindsets. “In the fixed mindset, people believe that their talents and abilities are fixed traits. They have a certain amount and that’s that; nothing can be done to change it. In the growth mindset, people believe that their talents and abilities can be developed through passion, education, and persistence.”
Jo states that the fixed mindset contributes to one of the biggest myths in mathematics: being good at math is a gift. She referenced her book, The Elephant in the Classroom (added it to my reading list) and showed the audience various television/movie clips that continue to perpetuate…
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Tables in CASIO FX-9860G Slim
The most popular Graphical Calculator for H2 Maths is currently the TI-84 PLUS series, but some students do use Casio Graphical Calculators.
The manual for CASIO FX-9860G Slim is can be found here:
http://edu.casio.com/products/fx9860g2/data/fx-9860GII_Soft_E.pdf
The information about Tables and how to generate a table is on page 121.
Generating tables is useful to solve some questions in sequences and series, and also probability. It makes guess and check questions much faster to solve.

Last week a friend who is a fourth grade teacher came to me with a math problem. The father of one of his students had showed him a trick for checking the result of a three-digit multiplication problem. The father had learned the trick as a student himself, but he didn’t know why it worked. My friend showed me the trick and asked if I had seen it before. This post describes this check and explains why it works.
Suppose you want to multiply 231 $latex \times $ 243. Working it out by hand, you get 56133. Add the digits in the answer (5+6+1+3+3) to get 18. Add the digits again to get 9. Stop now that you have a single digit.
Alternatively, do this digit adding beforehand. Adding the digits of 231 together, we get 6. Adding the digits of 243 together, we get 9. Multiply 6 $latex \times$ 9…
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Having a blog gives me a chance to defend myself against a number of people who took issue with a passage in Mathematics, A Very Short Introduction, where I made the tentative suggestion that an abstract approach to mathematics could sometimes be better, pedagogically speaking, than a concrete one — even at school level. This was part of a general discussion about why many people come to hate mathematics.
The example I chose was logarithms and exponentials. The traditional method of teaching them, I would suggest, is to explain what they mean and then derive their properties from this basic meaning. So, for example, to justify the rule that xa+b=xaxb one would say something like that if you have a xs followed by b xs and you multiply them all together then you are multiplying a+b xs all together.
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Today I had an experience that I have had many times before, and so, I imagine, has almost everybody (at least if they are old enough to be the kind of person who might conceivably read this blog post). I was in a queue in a chemist (=pharmacy=drugstore), and I knew that my particular item would be quick and easy to deal with. But I had to wait a while because in front of me was someone who had an item that was much more complicated and time-consuming. In this instance the complexity of the items was not due to their sizes, but a more common occurrence of the phenomenon is something that often happens to me in a local grocery: I want to buy just a pint of milk, say, and I find myself behind somebody who has a big basket of things, several of which have to be…
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Now that the project to upgrade my old multiple choice applet to a more modern and collaborative format is underway (see this server-side demo and this javascript/wiki demo, as well as the discussion here), I thought it would be a good time to collect my own personal opinions and thoughts regarding how multiple choice quizzes are currently used in teaching mathematics, and on the potential ways they could be used in the future. The short version of my opinions is that multiple choice quizzes have significant limitations when used in the traditional classroom setting, but have a lot of interesting and underexplored potential when used as a self-assessment tool.
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8(iv)
Using the model , estimate the total fertility rate for a particular country Z when its GDP per capita is USD$1000, giving your answer to 1 decimal place and comment on the reliability of the estimate.
First, we need to remove the outlier (40,6.6) as mentioned in part iii.
Then, performing linear regression with GC, (with variables ,
), we get:
Substituting , we get
(1 d.p.)
Since we cannot have a negative fertility rate (the average number of children that would be born to a woman ), the estimate obtained for is not reliable.
I’m in the happy state of just having finished marking exams for this year. There is very little of interest to say about the week that was removed from my life: it would be fun to talk about particularly bizarre mistakes, but I can’t really do that, especially as the results are not yet known (or even fully decided). However, one general theme emerged that made no difference to anybody’s marks. There seems to be a common misconception amongst many Cambridge undergraduates that I’d like to discuss here in the hope that I can clear things up for a few people. (It is an issue that I have discussed already on my web page, but rather than turning that into a blog post I’m starting again.)
The question where the misconception made itself felt was one about functions, injections, surjections, etc. I noticed that a lot of people wrote things…
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I’ve received quite a lot of inquiries regarding a recent article in the New York Times, so I am borrowing some space on this blog to respond to some of the more common of these, and also to initiate a discussion on maths education, which was briefly touched upon in the article.
Firstly, some links:
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As the previous discussion on displaying mathematics on the web has become quite lengthy, I am opening a fresh post to continue the topic. I’m leaving the previous thread open for those who wish to respond directly to some specific comments in that thread, but otherwise it would be preferable to start afresh on this thread to make it easier to follow the discussion.
It’s not easy to summarise the discussion so far, but the comments have identified several existing formats for displaying (and marking up) mathematics on the web (mathML, jsMath, MathJax, OpenMath), as well as a surprisingly large number of tools for converting mathematics into web friendly formats (e.g. LaTeX2HTML, LaTeXMathML, LaTeX2WP, Windows 7 Math Input, itex2MML, Ritex, Gellmu, mathTeX, WP-LaTeX, TeX4ht, blahtex, plastex, TtH, WebEQ, techexplorer…
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High school algebra marks a key transition point in one’s early mathematical education, and is a common point at which students feel that mathematics becomes really difficult. One of the reasons for this is that the problem solving process for a high school algebra question is significantly more free-form than the mechanical algorithms one is taught for elementary arithmetic, and a certain amount of planning and strategy now comes into play. For instance, if one wants to, say, write $latex {\frac{1,572,342}{4,124}}&fg=000000$ as a mixed fraction, there is a clear (albeit lengthy) algorithm to do this: one simply sets up the long division problem, extracts the quotient and remainder, and organises these numbers into the desired mixed fraction. After a suitable amount of drill, this is a task that can be accomplished by a large fraction of students at the middle school level. But if, for instance, one has to solve…
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Michael Gove, the UK’s Secretary of State for Education, has expressed a wish to see almost all school pupils studying mathematics in one form or another up to the age of 18. An obvious question follows. At the moment, there are large numbers of people who give up mathematics after GCSE (the exam that is usually taken at the age of 16) with great relief and go through the rest of their lives saying, without any obvious regret, how bad they were at it. What should such people study if mathematics becomes virtually compulsory for two more years?
A couple of years ago there was an attempt to create a new mathematics A-level called Use of Mathematics. I criticized it heavily in a blog post, and stand by those criticisms, though interestingly it isn’t so much the syllabus that bothers me as the awful exam questions. One might…
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In the diagram, the circumference of the external large circle is
1) longer, or
2) shorter, or
3) equal to,
the sum of the circumferences of all inner circles centered on the common diameter, tangent to each other.
Answer: 3) equal
circumference = π. diameter
Let d be the diameter of the external large circle C
Let dj be the diameter of the inner circle Cj
$latex \displaystyle d = \sum_{j} d_j$
$latex \displaystyle \pi. d = \pi. \sum_{j} d_j= \sum_{j}\pi.d_j$
Circumference of the external circle
= sum of circumferences of all inner circles
MI H2 Maths Prelim 2010 Paper 2 Q7 (P&C)
Question:
7) Two families are invited to a party. The first family consists of a man and both his parents while the second family consists of a woman and both her parents. The two families sit at a round table with two other men and two other women.
Find the number of possible arrangements if
(i) there is no restriction, [1]
(ii) the men and women are seated alternately, [2]
(iii) members of the same family are seated together and the two other women must be seated separately, [3]
(iv) members of the same family are seated together and the seats are numbered. [2]
Solution:
(i) (10-1)!=9!=362880
(ii) First fix the men’s sitting arrangement: (5-1)!
Then the remaining five women’s total number of arrangements are: 5!
Total=4! x 5!=2880
(iii) Fix the 2 families (as a group) and the 2 men: (4-1)! x 3! x 3!
(3! to permute each family)
By drawing a diagram, the two women have 4 slots to choose from, where order matters:
Total =
(iv)
We first find the required number of ways by treating the seats as unnumbered:
Since the seats are numbered, there are 10 choices for the point of reference, thus no. of ways =
I had a mathematical conversation yesterday with a 17-year-old boy who is in his second year of doing maths A-level. Although a sample of size 1 should be treated with caution, I’m pretty sure that the boy in question, who is very intelligent and is expected to get at least an A grade, has been taught as well as the vast majority of A-level mathematicians. If this is right, then what I discovered from talking to him was quite worrying.
The purpose of the conversation was to help him catch up with some work that he had missed through illness. The particular topics he wanted me to cover were integrating $latex \log x$, or $latex \ln x$ as he called it, and integration by parts. (Actually, after I had explained integration by parts to him, he told me that that hadn’t been what he had meant, but I don’t think…
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Shawn asked a good question in class yesterday about the differences between stratified sampling and quota sampling. In terms of sampling mechanism (i.e. the actual process by which cases are chosen from the population), it is clear that these two samples are different. Unclear, however, is why they would lead to different results.
Recall that stratified sampling is conducted by dividing a population into two or more strata by virtue of some characteristic, and taking random samples from each strata. This is done when a simple random sample of an entire population will likely not generate enough analyzable cases for a given group of particular interest.
Let’s say we want to study the income differences between blacks and whites in the United States. Unfortunately, we only have enough funding to distribute 500 questionnaires. Given that 10% of the population is black (made up, but reasonably approximate), a simple random…
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One of my students asked me how to solve 2007 Paper 1 Q8 (iii) using Foot of Perpendicular method.
The answer given in the TYS uses a sine method, which is actually shorter in this case, since we have found the angle in part (ii).
Nevertheless, here is how we solve the question using Foot of Perpendicular method.
(Due to copyright issues, I cannot post the whole question here, so please refer to your Ten Year Series.)
Firstly, let F be the foot of the perpendicular.
Then, ——– Eqn (1)
——– Eqn (2)
From Eqn (1),
Substituting into Eqn (2),
Substituting back into Eqn (1),
If you or a friend are looking for Maths tuition: O level, A level H2 JC (Junior College) Maths Tuition, IB, IP, Olympiad, GEP and any other form of mathematics you can think of.
Experienced, qualified (Raffles GEP, NUS Maths 1st Class Honours, NUS Deans List) and most importantly patient even with the most mathematically challenged.
So if you are in need of the solution to your mathematical woes, drop me a message!
Tutor: Mr Wu
Email: mathtuition88@gmail.com
Website: Singapore Maths Tuition | Patient and Dedicated Maths Tutor in Singapore
Landau’s beautiful proofs:
1= cos 0 = cos (x-x)
Opening cos (x-x):
1 = cos x.cos (-x) – sin x.sin (-x)
=> 1= cos² x + sin² x
[QED]
Let cos x= b/c, sin x = a/c
1= (b/c)² + (a/c)²
c² = b² + a²
=> Pythagoras Theorem
[QED]
Landau (1877-1938) was the successor of Minkowski at the Gottingen University (Math) before WW II.
Mental Trick
It was discovered by the Martial Art writer Liang Yusheng 武侠小说家 梁羽生 (《白发魔女传》作者), who met Hua Luogeng (华罗庚) @1979 in England:
2³= [8]
8³= 51[2]
3³= 2[7]
7³= 34[3]
The last digit pairs :
[2 <->8] , [3 <-> 7]
Others unchanged.
Example:
$latex \sqrt[3]{658503} = N$
Last three digits 503 <-> …[7]
First three digits 658:
(8³ =512)< 658 < (729 = 9³)
=> 8…
Answer : $latex \sqrt[3]{658503} = N$= 87
Note: Similar trick for opening $latex \sqrt[23] {200 digits}$ by an indian lady Ms Shakuntala (83) dubbed “Human computer”.
Verify:2,578,314 x 6,321,737 = 16,299,423,011,418 ?
2,578,314 => (2+5+7+8+3+1+4)) =30 => (3+0) = 3
6,321,737 => (6+3+2+1+7+3+7)=29 => 2+9 = 11 => (1+1) = 2
3 x 2 = 6
16,299,423,011,418 => (1+6+2+9+9+4+2+3+0+1+1+4+1+8) = 51 => (5+1) = 6
Correct !
Solution 2: Use Linear Algebra Eigenvalue equation: A.X = λ.X
A =S(x)= $Latex \frac{4}{5}(x-1)$ where x = coconuts
S(x)=λx
Since each iteration of the transformation caused the coconut status ‘unchanged’, which means λ = 1 (see remark below)
$Latex \frac{4}{5}(x-1)=x$
We get
x = – 4
S¹(x) = ⅘ (x-1)
S²(x) = ⅘( [⅘ (x-1)]-1)
= ⅘ (⅘ x -⅘ -1)
= (⅘)² x – (⅘)² – ⅘
Also by recursive, after the fifth monkey:
$Latex S^5 (x)$ = $Latex (\frac{4}{5})^5 (x-1)- (\frac{4}{5})^4-(\frac{4}{5})^3- (\frac{4}{5})^2- \frac{4}{5}$
$Latex S^5 (x)$ = $Latex (\frac{4}{5})^5 (x) – (\frac{4}{5})^5 – (\frac{4}{5})^4 – (\frac{4}{5})^3+(\frac{4}{5})^2 – \frac{4}{5}$
$Latex 5^5$ divides (x)
Minimum positive x= – 4 mod ($Latex 5^{5}$ )= $Latex 5^{5} – 4$= 3,121 [QED]
Note: The meaning of eigenvalue λ in linear transformation is the change by a scalar of λ factor (lengthening or shortening by λ) after the transformation. Here
λ = 1 because…
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