Singapore math

Singapore math (or Singapore maths in British English[1]) is a teaching method based on the national math curriculum used for kindergarten through sixth grade in Singapore.[2][3] It involves teaching students to learn and master fewer mathematical concepts at greater detail as well as having them learn these concepts using a three-step learning process.[2][3] The three steps are concrete, pictorial, and abstract. In the concrete step, students engage in hands-on learning experiences using concrete objects such as chips, dice, or paper clips.[4] This is followed by drawing pictorial representations of mathematical concepts. Students then solve mathematical problems in an abstract way by using numbers and symbols.[5]

The development of Singapore math began in the 1980s when the country’s Ministry of Education developed its own mathematics textbooks that focused on problem solving and heuristic model drawing.[3][6] Outside Singapore, these textbooks were adopted by several schools in the the United States (U.S.) and in other countries such as Canada, Israel, and the United Kingdom.[7][1][8] Early adopters of these textbooks in the U.S. included parents interested in homeschooling as well as a limited number of schools.[3] These textbooks became more popular since the release of scores from the Trends in International Mathematics and Science Study (TIMSS), which showed Singapore at the top of the world three times in fourth and eighth grade mathematics.[9] U.S. editions of these textbooks have since been adopted by a large number of school districts as well as charter and private schools.[3]

The bar model can be drawn as a comparison model to compare two bars of unequal lengths, which can then be used to solve a subtraction problem.

Small Group Maths Tuition at Bishan (O Level E Maths and A Maths)

Maths Tuition @ Bishan by Patient Tutor, NUS 1st Class Honours,

Ex-RI (GEP)

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Location: Block 230 Bishan Street 23 #B1-35 S(570230)

*Small Group Maths Tuition available in 2014 —

Registration/enquiries open now*

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Patient and Dedicated Maths Tutor available for Maths Tuition
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Subjects for tuition:
•O level (Secondary): E Maths, A Maths

Tutor is patient, experienced and qualified. (from Raffles

Institution (GEP), NUS Mathematics Dean’s List)

Please email us at mathtuition88@gmail.com for more details.

Website: https://mathtuition88.com/

O Level E Maths and A Maths Tuition starting next year at Bishan

O Level E Maths and A Maths Tuition starting next year at Bishan
————————–
View Mr Wu’s GEP Testimonial at https://mathtuition88.com/group-tuition/

Despite being in the Gifted Education Programme (GEP), Mr Wu is just an ordinary Singaporean. His secret to academic success is hard work and the Maths Techniques he has discovered by himself while navigating through the education system.

He would like to teach these techniques to students, hence choosing to become a full-time Mathematics tutor. Mr Wu has developed his own methods to check the answer, remember formulas (with understanding), which has helped a lot of students. Many Math questions can be checked easily, leading to the student being 100% confident of his or her answer even before the teacher marks his answer, and reducing the rates of careless mistakes.

Mr Wu’s friendly and humble nature makes him well-liked by students. Many of his students actually request for tuition by themselves! (not the parents) His students also look forward to tuition, instead of dreading tuition.

O Level E Maths and A Maths Tuition starting next year at Bishan, the best location in Central Singapore.

Timings are Monday 7-9pm, Thursday 7-9pm. Perfect for students who have CCA in the afternoon, or students who want to keep their weekends free.

Register with us now by email (mathtuition88@gmail.com). Vacancies will be allocated on a first-come-first-serve basis.

Thanks and wishing all a nice day.

E Maths Formula List / A Maths Formula Sheet

Attached below are the Formula Lists for E Maths and A Maths (O Level)

Do be familiar with all the formulas for Elementary Maths and Additional Maths inside, so that you know where to find it when needed!
Wishing everyone reading this all the best for their exams. 🙂

E Maths Formula List

A Maths Formula List

Maths Tuition

For Mathematics Tuition, contact Mr Wu at:

Email: mathtuition88@gmail.com

O Level E Maths and A Maths Tuition starting next year at Bishan

O Level E Maths and A Maths Tuition starting next year at Bishan
————————–
View Mr Wu’s GEP Testimonial at

https://mathtuition88.com/group-tuition/

Despite being in the Gifted Education Programme (GEP), Mr Wu is just an ordinary Singaporean. His secret to academic success is hard work and the Maths Techniques he has discovered by himself while navigating through the education system.

He would like to teach these techniques to students, hence choosing to become a full-time Mathematics tutor. Mr Wu has developed his own methods to check the answer, remember formulas (with understanding), which has helped a lot of students. Many Math questions can be checked easily, leading to the student being 100% confident of his or her answer even before the teacher marks his answer, and reducing the rates of careless mistakes.

Mr Wu’s friendly and humble nature makes him well-liked by students. Many of his students actually request for more tuition by themselves! (not the parents)

O Level E Maths and A Maths Tuition starting next year at Bishan, the best location in Central Singapore.

Timings are Monday 7-9pm, Thursday 7-9pm. Perfect for students who have CCA in the afternoon, or students who want to keep their weekends free.

Register with us now by email (mathtuition88@gmail.com). Vacancies will be allocated on a first-come-first-serve basis.

Thanks and wishing all a nice day.

E Maths Group Tuition Centre; Clementi Town Secondary School Prelim 2012 Solution

Q5) The speed of a boat in still water is 60 km/h.

On a particular day, the speed of the current is $x$ km/h.

(a) Find an expression for the speed of the boat

(I) against the current, [1]

Against the current, the boat would travel slower! This is related to the Chinese proverb, 逆水行舟，不进则退, which means “Like a boat sailing against the current, we must forge ahead or be swept downstream.”

Hence, the speed of the boat is $60-x$ km/h.

(ii) with the current. [1]

$60+x$ km/h

(b) Find an expression for the time required to travel a distance of 80km

(I) against the current,  [1]

Recall that $\displaystyle \text{Time}=\frac{\text{Distance}}{\text{Speed}}$

Hence, the time required is $\displaystyle \frac{80}{60-x}$ h

(ii) with the current. [1]

$\displaystyle \frac{80}{60+x}$ h

(c) If the boat takes 20 minutes longer to travel against the current than it takes to travel with the current, write down an equation in $x$ and show that it can be expressed as $x^2+480x-3600=0$   [2]

Note: We must change 20 minutes into 1/3 hours!

$\frac{80}{60-x}=\frac{1}{3}+\frac{80}{60+x}$

There are many ways to proceed from here, one way is to change the Right Hand Side into common denominator, and then cross-multiply.

$\displaystyle \frac{80}{60-x}=\frac{60+x}{3(60+x)}+\frac{240}{3(60+x)}=\frac{300+x}{3(60+x)}$

Cross-multiply,

$240(60+x)=(300+x)(60-x)$

$14400+240x=18000-300x+60x-x^2$

$x^2+480x-3600=0$ (shown)

(d) Solve this equation, giving your answers correct to 2 decimal places. [2]

$\displaystyle x=\frac{-480\pm\sqrt{480^2-4(1)(-3600)}}{2}=7.386 \text{ or } -487.386$

Answer to 2 d.p. is $x=7.39 \text{ or } -487.39$

(e) Hence, find the time taken, in hours, by the boat to complete a journey of 500 km against the current. [2]

Now we know that the speed of the current is 7.386 km/h.

Hence, the time taken is $\frac{500}{60-7.386}=9.50$ h

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Maths can be fun too!
Build up interest in Mathematics by trying out some of these interesting Maths Riddles.

The riddle

Three guests check into a hotel room. The clerk says the bill is $30, so each guest pays$10. Later the clerk realizes the bill should only be $25. To rectify this, he gives the bellhop$5 to return to the guests. On the way to the room, the bellhop realizes that he cannot divide the money equally. As the guests didn’t know the total of the revised bill, the bellhop decides to just give each guest $1 and keep$2 for himself. Each guest got $1 back: so now each guest only paid$9; bringing the total paid to $27. The bellhop has$2. And $27 +$2 = $29 so, if the guests originally handed over$30, what happened to the remaining \$1?

Try it out before looking at the answer!