Secondary Maths Tuition: Kinematics Question



acceleration of car =\frac{12}{6}=2m/s^2


v=2\times 10=20

Let T be the time (in seconds) when the car overtakes the truck.

Total distance travelled by car at T seconds = area under graph = \frac{1}{2}(T-5)(2(T-5))

(2(T-5) is the velocity of car at T seconds, it is obtained in the same way as we calculated v.)

Total distance travelled by truck at T seconds = \frac{1}{2}(6)(12)+\frac{1}{2}(15-6)(12+16)+16(T-15)

Equating the two distances will lead to a quadratic equation T^2-26T+103=0

Solving that gives T=21.12s or T=4.876s (rejected as car only starts at t=5)

21.12-5=16.1s (3 s.f.)

Author: mathtuition88

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