Tag Archives: Triangle

Parallelogram Maths Tuition: Solution

Solution: (a) We have (opp. angles of parallelogram) (opp. sides of parallelogram) (opp. sides of parallelogram) Thus, (SAS) Similarly, (SAS) (SAS) Thus, (proved) (b) (vert. opp. angles) (alt. angles) (alt. angles) Thus, is similar to (AAA) Hence, Thus, (proved)

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Congruent Triangles Geometry Maths Tuition: Solution

Solution: (a) (given) BE is a common side for both triangles and BD=EC (given) Therefore, (SAS) (proved) (b) Since we have Thus, Therefore, is an isosceles triangle. Thus, (proved)

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Congruent Triangles Maths Tuition: Solution

Solution: BS=BE+ES=ST+ES=ET BA=DT (given) Thus, is congruent to (RHS) Hence Thus DT//BA (alt. angles) (Proved) By Pythagoras’ Theorem, we have Hence and are congruent (SSS). Hence Thus DB//TA (alt. angles) Therefore, ABDT is a parallelogram since it has two pairs … Continue reading

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