This is an old arabic problem:
An old man had 11 horses. When he died, his will stated the following distribution to his 3 sons:
1/2 gives to the eldest son,
1/4 for 2nd son,
1/6 for 3rd son.
Find: how many horses each son gets ?
There are 2 methods to solve: first using simple arithmetic trick without knowing the theory behind; the second method will explain the first method “from an advanced standpoint” – Number Theory (Felix Klein’s Vision )
1) Arithmetic trick:
11 is odd, not divisible by 2, 4 and 6.
Loan 1 horse to the old man:
11+1 = 12
1st son gets: 12/2 = 6 horses
2nd son gets:12/4 = 3 horses
3rd son gets: 12/6 = 2 horses
Total = 6+3+2=11 horses
Up to you if you want the old man to return the 1 loan horse 🙂
Strange! WHY ?
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