The mass of particles of a certain radioactive chemical element (O Level Math Tuition Question)

The mass of particles of a certain radioactive chemical element is halved every 10 months.  During a chemical experiment, the initial mass of particles of the chemical element is 3mg.

(i) write down an expression, in terms of t, for the mass of particles after t years.
(ii) Hence, find the value of t, if the mass is reduced to 0.046875 mg after t years.

Solution:

(i)

$1\: \text{year} = 12\: \text{months}$

Therefore, $t\: \text{years}=12t\: \text{months}$.

How many 10 months are there in $t\: \text{years}$? (Ans: $\frac{12t}{10}=1.2t$)

Hence, the mass of particles after $t$ years is $3\times(0.5)^{1.2t}$ mg.

(ii)
We need to solve $3(0.5)^{1.2t}=0.046875$.

Dividing by 3, we have $(0.5)^{1.2t}=0.015625$.

Ln both sides, we have $1.2t\ln{0.5}=\ln{0.015625}$.

Hence, $t=\frac{\ln{0.015625}}{1.2\ln{0.5}}=5$.

If you liked our solution above, please consider signing up for Maths Tuition with us! 🙂

Author: mathtuition88

http://mathtuition88.com

This site uses Akismet to reduce spam. Learn how your comment data is processed.