Implement the myAtoi(string s) function, which converts a string to a 32-bit signed integer (similar to C/C++’s atoi function).
The algorithm for myAtoi(string s) is as follows:
- Read in and ignore any leading whitespace.
- Check if the next character (if not already at the end of the string) is
'-'or'+'. Read this character in if it is either. This determines if the final result is negative or positive respectively. Assume the result is positive if neither is present. - Read in next the characters until the next non-digit character or the end of the input is reached. The rest of the string is ignored.
- Convert these digits into an integer (i.e.
"123" -> 123,"0032" -> 32). If no digits were read, then the integer is0. Change the sign as necessary (from step 2). - If the integer is out of the 32-bit signed integer range
[-231, 231 - 1], then clamp the integer so that it remains in the range. Specifically, integers less than-231should be clamped to-231, and integers greater than231 - 1should be clamped to231 - 1. - Return the integer as the final result.
Note:
- Only the space character
' 'is considered a whitespace character. - Do not ignore any characters other than the leading whitespace or the rest of the string after the digits.
Leetcode Solution (Python)
class Solution:
def myAtoi(self, s: str) -> int:
# Positive sign
positive = True
result_str = ''
digits = ['0','1','2','3','4','5','6','7','8','9']
signs = ['+','-']
# Has the first non-space been encountered
started = False
# Has the first sign been encountered
signed = False
for i in range(0,len(s)):
if (signed == True or started == True) and s[i] in signs:
break
if s[i]!= ' ':
started = True
if s[i] in signs:
signed = True
if s[i]=='-':
positive = False
elif s[i] in digits:
result_str += s[i]
if started==True and s[i] not in digits and s[i] not in signs:
break
#print(result_str)
if result_str=='':
return 0
else:
result_int = int(result_str) if positive==True else -int(result_str)
# Clamp Range:
MIN_INT = -2**31
MAX_INT = 2**31-1
if result_int < MIN_INT:
result_int = MIN_INT
elif result_int > MAX_INT:
result_int = MAX_INT
return result_int
Elements of Programming Interviews in Python: The Insiders’ Guide