Bi-quadratic Equation by Vedic Math
Solve
$latex (x+7)^4+(x+5)^4=706$
Let y = x + 6 = average of (x+5, x+7)
$latex (y+1)^4+(y-1)^4=706$
Cancel terms y, y³:
$latex 2y^4+12y^2+2=706$
$latex y^4+6y^2-352=0$
$latex y^2=16$ or
$latex y^2=-22$
y= ±4 or ±$latex sqrt{-22}$
y=x+6
x=-2, -10, ± $latex sqrt{-22}-6$
Mathtuition88 